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RAJASTHAN ­ PET Rajasthan PET Solved Paper-2009

  • question_answer
    For the decomposition of\[{{N}_{2}}O\]and\[{{O}_{2}}\]in presence of at, the velocity constant, k is \[k=5\times {{10}^{11}}{{e}^{-30,000/T}}\] For this, the activation energy is (in kJ\[mo{{l}^{-1}}\])

    A)  2.494             

    B)  24.94

    C)  249.4             

    D)  2494

    Correct Answer: C

    Solution :

     [c] Given,\[k=5\times {{10}^{11}}{{e}^{-30,000/T}}\]          ...(i) Arrhenius equation is as \[k=A{{e}^{-{{E}_{a}}/RT}}\]             ...(ii) From Eqs. (i) and (ii) \[-\frac{30000}{T}=-\frac{{{E}_{a}}}{RT}\] \[\therefore \] \[{{E}_{a}}=30,000\times R\] \[=30,000\times 8.314\] \[=249420\text{ }J\,mo{{l}^{-1}}\] \[=249.42\text{ }kJ\text{ }mo{{l}^{-1}}\]


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