A) \[+0.76\]
B) \[-0.76\]
C) \[-0.38\]
D) \[+0.38\]
Correct Answer: B
Solution :
\[\because \] \[{{T}_{b}}=100.2{}^\circ C\] \[\therefore \] \[\Delta {{T}_{b}}=100.2-100=0.2{}^\circ C\] \[\Delta {{T}_{b}}={{K}_{b}}\times m\] \[m=\frac{\Delta {{T}_{b}}}{{{K}_{b}}}=\frac{0.2}{0.5}=0.4\] \[\Delta {{T}_{f}}={{K}_{f}}\times m=1.9\times 0.4\] \[=0.76{}^\circ C\] \[\Delta {{T}_{f}}={{T}_{o}}-\Delta {{T}_{f}}=0-0.76\] \[=-0.76{}^\circ C\]
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