A) \[B>C>A\]
B) \[B>A>C\]
C) \[A>B>C\]
D) \[C>B>A\]
Correct Answer: A
Solution :
Among\[1{}^\circ ,2{}^\circ \]and\[3{}^\circ \]amines, the primary amine has the maximum strength to form the H-bond. The dipole-dipole attraction force also works between these molecules, hence the boiling point of primary amine is maximum. Between\[2{}^\circ \]and\[3{}^\circ \]amines, the tertiary amines does not form H-bond while secondary amine has some strength to form H-bond. Hence, the order of boiling point is as; \[\underset{\begin{smallmatrix} n-butyl\text{ }amine \\ \,\,\,\,1{}^\circ amine \\ \,\,\,\,\,\,\,(B) \end{smallmatrix}}{\mathop{{{C}_{4}}{{H}_{9}}N{{H}_{2}}}}\,>\underset{\begin{smallmatrix} diethyl\text{ }amine \\ \,\,\,\,\,\,\,\,\,2{}^\circ amine \\ \,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,(C) \end{smallmatrix}}{\mathop{{{({{C}_{2}}{{H}_{5}})}_{2}}NH}}\,>\underset{\begin{smallmatrix} ethyl\text{ }diethyl\text{ }amine \\ \,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,3{}^\circ amine \\ \,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,(A) \end{smallmatrix}}{\mathop{{{C}_{2}}{{H}_{5}}N{{(C{{H}_{3}})}_{2}}}}\,\]
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