A) equal to\[C{{D}_{4}}\]
B) double the rate of \[C{{D}_{4}}\]
C) 12 times the rate of\[C{{D}_{4}}\]
D) less than the rate of\[C{{D}_{4}}\]
Correct Answer: C
Solution :
The rate of reaction of\[C{{H}_{4}}\]is greater than \[C{{D}_{4}}\]because the activation energy of\[C{{H}_{4}}\]is less than the\[C{{D}_{4}}\]. Hence, the rate of free radical chlorination of\[C{{H}_{4}}\]is greater than\[C{{D}_{4}}\].
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