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RAJASTHAN ­ PET Rajasthan PET Solved Paper-2010

  • question_answer
    A resonant AC circuit contains a capacitor of capacitance\[{{10}^{-6}}F\]and an inductor of\[{{10}^{-4}}H\]The frequency of electrical oscillator will be

    A)  \[{{10}^{5}}Hz\]          

    B)  10 Hz

    C)  \[\frac{{{10}^{5}}}{2\pi }Hz\]            

    D)  \[\frac{10}{2\pi }Hz\]

    Correct Answer: A

    Solution :

     Frequency, \[v=\frac{1}{2\pi \sqrt{LC}}\] \[=\frac{I}{2\pi \sqrt{{{10}^{-6}}\times {{10}^{-4}}}}=\frac{{{10}^{5}}}{2\pi }Hz\]


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