A) 4 g
B) 4.22 g
C) 1.13 g
D) 10 g
Correct Answer: C
Solution :
\[\frac{{{p}_{0}}{{V}_{0}}}{{{T}_{0}}}=\frac{pV}{T}\] \[\frac{760\times m}{1.2\times 273}=\frac{768\times 1}{294}\] \[=\frac{768\times 1.2\times 273}{760\times 294}\] \[=1.13g\]You need to login to perform this action.
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