A) glycollic acid
B) \[\alpha -\]hydroxy propionic acid
C) succinic acid
D) malonic acid
Correct Answer: D
Solution :
\[C{{H}_{3}}COOH\xrightarrow[{}]{B{{r}_{2}}/P}\underset{'Y'}{\mathop{BrC{{H}_{2}}-COOH}}\,\] \[\xrightarrow[{}]{KCN(alc)}NC-C{{H}_{2}}COOH\] \[\xrightarrow[{}]{{{H}_{3}}{{O}^{+}}}\underset{\begin{smallmatrix} malonic\text{ }acid \\ \,\,\,\,\,\,\,\,\,\,\,'X' \end{smallmatrix}}{\mathop{HOOC-C{{H}_{2}}-COOH}}\,\]You need to login to perform this action.
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