A) chain isomerism
B) position isomerism
C) chain as well as position isomerism
D) functional isomerism
Correct Answer: C
Solution :
The structures of the given compounds are as \[{{H}_{3}}\overset{3}{\mathop{C}}\,-\underset{\begin{smallmatrix} | \\ Br \end{smallmatrix}}{\overset{\begin{smallmatrix} C{{H}_{3}} \\ | \end{smallmatrix}}{\mathop{^{2}C}}}\,-\overset{1}{\mathop{C}}\,{{H}_{3}}\]\[\overset{4}{\mathop{C}}\,{{H}_{3}}\overset{3}{\mathop{C}}\,{{H}_{2}}\overset{2}{\mathop{C}}\,{{H}_{2}}\overset{1}{\mathop{C}}\,{{H}_{2}}Br\] Since in these, the chain of carbon atoms and the position of functional group Ye, Br both are different, they exhibit chain as well as position isomerism.You need to login to perform this action.
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