A) \[{{10}^{6}}\]
B) zero
C) \[4\times {{10}^{6}}\]
D) \[4\times {{10}^{4}}\]
Correct Answer: C
Solution :
Here \[\frac{1}{2}m{{v}^{2}}=eV\] \[{{v}^{2}}=\frac{2eV}{m}\] Putting \[e=1.6\times {{10}^{-19}}C,\text{ }V=45.5\]volt and \[n=9.1\times {{10}^{-31}}kg\] \[{{v}^{2}}=16\times {{10}^{12}}\] \[v=4\times {{10}^{6}}m{{s}^{-1}}\]
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