RAJASTHAN ­ PET Rajasthan PET Solved Paper-2011

  • question_answer
    Three identical charges placed at the vertices of an equilateral triangle. The force experienced by each charge \[\left( if\,k=\frac{1}{4}\pi {{\varepsilon }_{0}} \right)\] is

    A)  \[2k\,\frac{{{q}^{2}}}{{{r}^{2}}}\]

    B)  \[\frac{k{{q}^{2}}}{2{{r}^{2}}}\]

    C)  \[\sqrt{3}k\frac{{{q}^{2}}}{{{r}^{2}}}\]

    D)  \[\frac{k{{q}^{2}}}{\sqrt{2{{r}^{2}}}}\]

    Correct Answer: C

    Solution :

     Force experienced by each charge \[F=\sqrt{F_{1}^{2}+F_{2}^{2}+2{{F}_{1}}{{F}_{2}}\cos \theta }\] \[F=\sqrt{{{\left( \frac{k{{q}_{2}}}{{{r}^{2}}} \right)}^{2}}+{{\left( \frac{k{{q}^{2}}}{{{r}^{2}}} \right)}^{2}}+2\left( \frac{k{{q}^{2}}}{{{r}^{2}}} \right)\left( \frac{k{{q}^{2}}}{{{r}^{2}}} \right)\cos 60{}^\circ }\] \[F=\frac{k{{q}^{2}}}{{{r}^{2}}}\sqrt{3}\] \[F=\frac{\sqrt{3}k{{q}^{2}}}{{{r}^{2}}}\]


You need to login to perform this action.
You will be redirected in 3 sec spinner