A) \[r.(i+2j-k)=3\]
B) \[r.(i+2j-k)=6\]
C) \[r.(-i-2j+k)=3\]
D) None of the above
Correct Answer: A
Solution :
The position vector of any point on the given line is \[i+j+\lambda (2i+j+4k)\] or \[(2\lambda +1)i+(\lambda +1)\hat{j}+4\lambda k\] which lies on\[r.(i+2j+k)=3\] Hence, the plane\[r.(i+2j-k)=3\] contains the given line.
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