RAJASTHAN ­ PET Rajasthan PET Solved Paper-2012

  • question_answer
    The rms velocity of oxygen molecule at\[27{}^\circ C\]is (Atomic weight of oxygen =16)

    A)  \[402.5\,m{{s}^{-1}}\]   

    B)  \[400.5\text{ }m{{s}^{-1}}\]

    C)  \[483.5\text{ }m{{s}^{-1}}\]   

    D)  \[532.5\text{ }m{{s}^{-1}}\]

    Correct Answer: C

    Solution :

     Temperature \[T=27{}^\circ C=273+27=300K\] Atomic weight of oxygen =16 \[\therefore \] Molecular weight of oxygen, \[M=2\times 16=32\] \[R=8.31\text{ }J\text{ }mo{{l}^{-1}}{{K}^{-1}}\] So, the rms velocity, \[C=\sqrt{\frac{3RT}{M}}\] \[=\sqrt{\frac{3\times 8.31\times 300}{32}}=483.5\,m{{s}^{-1}}\]


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