A) \[\frac{5}{6}\Omega \]
B) \[\frac{6}{5}\Omega \]
C) \[\frac{6}{25}\Omega \]
D) \[\frac{25}{6}\Omega \]
Correct Answer: D
Solution :
The resistance of portion of resistor subtending an angle of\[60{}^\circ \]at the centre of the circle \[=\frac{1}{2}\times 30=5\,\Omega \] Now\[5\,\Omega ,\]and the resistance\[25\,\Omega \]of the remaining portion are connected in parallel \[\therefore \] \[\frac{1}{R}=\frac{1}{5}+\frac{1}{25}=\frac{6}{25}\Omega \] So, the effective resistance between X and Y \[=\frac{25}{6}\Omega \]
You need to login to perform this action.
You will be redirected in
3 sec
