RAJASTHAN ­ PET Rajasthan PET Solved Paper-2012

  • question_answer
    The equation of a wave is represented by \[y={{10}^{-4}}\sin \left( 100t-\frac{x}{10} \right)m,\]the velocity of the wave will be

    A)  \[0.1\text{ }m{{s}^{-1}}\]     

    B)  \[10\text{ }m{{s}^{-1}}\]

    C)  \[100\text{ }m{{s}^{-1}}\]     

    D)  \[1000\text{ }m{{s}^{-1}}\]

    Correct Answer: D

    Solution :

     The given equation comparing with standard equation \[y=A\sin \frac{2\pi }{\lambda }(vt-x)\] \[\therefore \] \[\frac{2\pi }{\lambda }v=100\]and \[\frac{2\pi }{\lambda }=\frac{1}{10}\] \[\Rightarrow \] \[v=1000\text{ }m{{s}^{-1}}\]


You need to login to perform this action.
You will be redirected in 3 sec spinner