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  3. RAJASTHAN ­ PET

RAJASTHAN ­ PET Rajasthan PET Solved Paper-2012

  • question_answer
    Two blocks of masses \[{{m}_{1}}\] and \[{{m}_{2}}\] are placed in contact with each other on a rough horizontal surface having coefficient of friction\[\mu \]as shown in figure. The minimum horizontal force F required to move the block\[{{m}_{1}}\]

    A)  \[\mu ({{m}_{1}}-{{m}_{2}})g\]

    B)  \[\mu ({{m}_{2}}-{{m}_{1}})g\]

    C)  \[\mu {{m}_{1}}g\]

    D)  \[\mu ({{m}_{1}}+{{m}_{2}})g\]

    Correct Answer: C

    Solution :

     For motion,\[F\ge \]force of friction\[(f)\] But \[f=\mu N=\mu ({{m}_{1}}+{{m}_{2}})g\] \[\therefore \] \[F\ge \mu ({{m}_{1}}+{{m}_{2}})=g\]


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