A) \[C{{H}_{3}}CON{{H}_{2}}~\]
B) \[C{{H}_{3}}NO\]
C) \[N{{H}_{2}}CON{{H}_{2}}\]
D) \[C{{H}_{3}}N{{H}_{2}}\]
Correct Answer: C
Solution :
\[N{{H}_{2}}-\underset{{}}{\mathop{\underset{O}{\mathop{\underset{||}{\mathop{C}}\,}}\,}}\,-N{{H}_{2}}+2NaN{{O}_{2}}+2HCl\xrightarrow{{}}\]. Urea \[C{{O}_{2}}+3{{H}_{2}}O+2{{N}_{2}}+NaCl\]
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