A) \[Al{{(OH)}_{3}}\]
B) \[Al\]
C) \[Fe\]
D) \[NaAl{{O}_{2}}\]
Correct Answer: D
Solution :
\[A{{l}_{2}}{{O}_{3}}.2{{H}_{2}}O+2NaOH\xrightarrow{\Delta }\] \[\underset{Sod-\text{meta}\,\text{aluminate}}{\mathop{2NaAl{{O}_{2}}}}\,-3{{H}_{2}}O\]
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