A) \[C{{H}_{3}}\text{ }COC{{H}_{3}}\]
B) \[C{{H}_{3}}C{{H}_{2}}COOH\]
C) \[C{{H}_{3}}C{{H}_{2}}CHO\]
D) \[C{{H}_{3}}-CH=C{{H}_{2}}\]
Correct Answer: A
Solution :
\[C{{H}_{3}}-\underset{\Pr opyl}{\mathop{C\equiv CH}}\,+{{H}_{2}}O\xrightarrow{{{H}^{+}}/H{{g}^{2+}}}\underset{Acetone}{\mathop{C{{H}_{3}}COC{{H}_{3}}}}\,\]
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