A) \[{{10}^{-2}}M\]
B) \[2\times 10M\]
C) \[0.001M\]
D) \[0.0001M\]
Correct Answer: A
Solution :
\[pH=-\log {{H}^{+}},\] \[[{{H}^{+}}]={{10}^{-ph}}\] \[[{{H}^{+}}]={{10}^{-2}}M\]
You need to login to perform this action.
You will be redirected in
3 sec
