RAJASTHAN PMT Rajasthan - PMT Solved Paper-1995

  • question_answer
    Two charges\[4q\]and\[q\] are placed at a distance\[I\] another charge Q is placed at the midpoint of line joining the charges\[4q\]and\[q\] If net force on charge\[q\] is zero, then value of \[Q\] is:

    A) \[+q\]                  

    B)        \[-q\]  

    C) \[+2q\]                

    D)                        \[3q\]

    Correct Answer: B

    Solution :

    On charge Q, both 4q and q charge apply force. Net force of Q should be zero. \[K\frac{4q.\,\,q}{{{l}^{2}}}+\frac{K\,\,Q.q}{{{(1/2)}^{2}}}=0\] \[Q=-q\]


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