A) \[4\times {{10}^{-8}}\]
B) \[8\times {{10}^{-12}}\]
C) \[16\times {{10}^{-12}}\]
D) \[32\times {{10}^{-12}}\]
Correct Answer: D
Solution :
In saturated solution of silver chromate. \[AgCr{{O}_{4}}\xrightarrow{{}}\underset{\begin{smallmatrix} 2\times 2\times {{10}^{-2}}m \\ =4\times {{10}^{-4}}m \end{smallmatrix}}{\mathop{2A{{g}^{+}}}}\,+\underset{2\times {{10}^{-4}}m}{\mathop{Cr{{O}_{4}}^{-\,\,-}}}\,\] (according to questions) \[AgCr{{O}_{4}}[Ksp]={{[A{{g}^{+}}]}^{2}}\times [Cr{{O}_{4}}^{-\,\,-}]\] \[={{[4\times {{10}^{-4}}]}^{2}}\times [2\times {{10}^{-4}}]\] \[=32\times {{10}^{-12}}\]
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