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RAJASTHAN PMT Rajasthan - PMT Solved Paper-1995

  • question_answer
    \[_{\text{90}}\text{T}{{\text{h}}^{\text{232}}}\]disintegrate continuously and finally converts into\[_{\text{82}}\text{P}{{\text{b}}^{\text{208}}}\text{,}\]then number of \[\alpha \] and \[\] particles produced are respectively:

    A)  \[4,6~\]                              

    B)         \[6,4\]  

    C)         \[3,2\]                 

    D)                         \[2,3\]

    Correct Answer: B

    Solution :

                    According to decay equation thorium \[_{90}T{{h}^{232}}{{\xrightarrow{{}}}_{82}}P{{b}^{208}}+6\alpha +4\beta \]


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