A) \[1.5\,\times {{10}^{-4}}\]
B) \[1.2\pi \times {{10}^{-4}}\]
C) \[0.3\pi \times {{10}^{-4}}\]
D) \[0.6\pi \times {{10}^{-4}}\]
Correct Answer: B
Solution :
Work done \[W=T.2A\] \[=0.05\times 2\times 4\pi ({{r}_{2}}^{2}-{{r}_{1}}^{2})\] \[=0.05\times 2\times 4\pi (2\times {{10}^{-4}}-1\times {{10}^{-4}})\] \[=1.2\pi \times {{10}^{-4}}J\]
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