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RAJASTHAN PMT Rajasthan - PMT Solved Paper-1995

  • question_answer
    Two waves of intensity \[I\]and\[4I\] super impose on each other.  Then  in interference maximum and minimum intensity are respectively:

    A)  \[3I\]and\[2I\]                

    B)                         \[25I\] and \[9I\]                            

    C)         \[9I\] and \[I\]                 

    D)                         \[5I\] and \[3I\]

    Correct Answer: C

    Solution :

    \[{{I}_{\max }}=I+4I+2\sqrt{I.4I}=9I\] \[{{I}_{\max }}=I+4I-2\sqrt{I.4I}=I\]


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