A) \[\frac{h}{2\pi }\]
B) \[\frac{h}{\pi }\]
C) \[\frac{h}{\pi r}\]
D) \[\frac{h}{2\pi r}\]
Correct Answer: B
Solution :
Angular momentum of electron \[=n\frac{h}{2\pi }\] For \[n=2\]angular momentum \[=2\times \frac{h}{2\pi }\] \[\therefore \] angular momentum \[=\frac{h}{\pi }\]
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