RAJASTHAN PMT Rajasthan - PMT Solved Paper-1995

  • question_answer
    In an X-ray tube, electrons are accelerated by a potential difference V, the minimum wavelength of emitted X-rays is:

    A) \[\frac{12400}{V}m\]                     

    B)        \[\frac{12400}{V}\overset{0}{\mathop{\text{A}}}\,\]     

    C)        \[\frac{1.24}{V}\overset{0}{\mathop{\text{A}}}\,\]                        

    D)        \[\frac{V}{12400}\overset{0}{\mathop{\text{A}}}\,\]

    Correct Answer: B

    Solution :

                    Minimum wavelength of X-rays \[{{\lambda }_{\min }}=\frac{12400}{V}\overset{\text{o}}{\mathop{\text{A}}}\,\]


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