A) \[{{}_{\text{0}}}\text{ }\!\!\times\!\!\text{ 1}{{\text{0}}^{\text{-19}}}\text{T}\]
B) \[\text{1}\text{.6}{{}_{\text{0}}}\text{ }\!\!\times\!\!\text{ 1}{{\text{0}}^{\text{-19}}}\text{T}\]
C) \[\frac{{{}_{\text{0}}}}{2}\text{ }\!\!\times\!\!\text{ 1}{{\text{0}}^{\text{-19}}}\text{T}\]
D) \[\text{2}{{}_{\text{0}}}\text{ }\!\!\times\!\!\text{ 1}{{\text{0}}^{\text{-19}}}\text{T}\]
Correct Answer: A
Solution :
Magnetic field \[B=\frac{{{\mu }_{0}}I}{2r}\] \[=\frac{{{\mu }_{0}}\times 1.6\times {{10}^{-19}}}{2\times 0.8}\] \[\left\{ I=\frac{q}{t}=\frac{3.2\times {{10}^{-19}}}{2}=1.6\times {{10}^{-19}} \right\}\] \[={{\mu }_{0}}\times {{10}^{-19}}T\]
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