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RAJASTHAN PMT Rajasthan - PMT Solved Paper-1995

  • question_answer
    Side of a square coil is 4 cm. A magnetic field normal to plane of coil is changing at a rate of 0.4 tesla/ sec. If resistance of coil is \[2\times {{10}^{-3}}\,ohm,\] then induced current is:

    A)  0.16 A                  

    B)         0.32 A

    C)         3.2 A                    

    D)                         1.6 A

    Correct Answer: B

    Solution :

    Induced current \[I=\frac{A}{R}\,\,\,\frac{\Delta B}{\Delta t}\] \[=\frac{16\times {{10}^{-4}}}{2\times {{10}^{-3}}}\times \frac{0.4}{1}=0.32A\]                 


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