2. Solved Papers
  3. RAJASTHAN PMT

RAJASTHAN PMT Rajasthan - PMT Solved Paper-1995

  • question_answer
    In an A.C. circuit current and voltage are:                 \[i={{i}_{0}}\,\sin \,(\omega t-\pi /2),e={{e}_{0}}\,\sin \,\omega t\]                 then average power consumed in the circuit is:

    A)  \[\frac{1}{2}\,{{i}_{0}}{{e}_{0}}\,watt\]                                

    B)        \[{{i}_{0}}{{e}_{0}}\] watt            

    C)         \[ie\]watt                          

    D)         zero

    Correct Answer: D

    Solution :

    \[i={{i}_{0}}\sin (\omega t\,-\pi /2),\,e={{e}_{0}}\sin \omega t\] Phase difference \[=\pi /2\] Average power loss \[={{i}_{rms}}\times {{e}_{rms}}\,\cos \phi \] \[={{i}_{rms}}\times {{e}_{rms}}\,\cos \,\pi /2=0\]                                 \[\left\{ \cos \frac{\pi }{2}=0 \right\}\]


You need to login to perform this action.
You will be redirected in 3 sec spinner