A) \[HgC{{l}_{2}}\],
B) \[ZnC{{l}_{2}}\]
C) \[{{C}_{2}}{{H}_{2}}\]
D) \[C{{F}_{2}}C{{l}_{2}}\]
Correct Answer: D
Solution :
\[HgC{{l}_{2}},\,ZnC{{l}_{2}},\,{{C}_{2}}{{H}_{5}}\] show the \[sp\] hybridisation but \[C{{F}_{2}}C{{l}_{2}}\] show \[s{{p}^{3}}\] hybridisation.
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