A) \[49\]
B) \[0.143\]
C) \[Erors\,0.02\]
D) \[7\]
Correct Answer: B
Solution :
\[{{H}_{2}}+{{I}_{2}}2HI\] For this reaction the value of K = 49 \[2HI{{H}_{2}}+{{I}_{2}}\] for this reaction the value of \[{{K}_{1}}=\frac{1}{K}=\frac{1}{49}\]. \[HI\frac{1}{2}{{H}_{2}}+\frac{1}{2}{{I}_{2}}\] For this reaction the value of \[{{K}_{2}}=\sqrt{\frac{1}{K}}\] \[=\sqrt{\frac{1}{49}}=\frac{1}{7}=0.143\]
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