RAJASTHAN PMT Rajasthan - PMT Solved Paper-1996

  • question_answer
    The solubility \[C{{a}_{3}}{{(P{{O}_{4}})}_{2}}\] is s mole. What is the solubility product of \[C{{a}_{3}}{{(P{{O}_{4}})}_{2}}\]?

    A)  \[8{{s}^{3}}\]                   

    B)                         \[9{{s}^{2}}\]                   

    C)                         \[108{{s}^{5}}\]                               

    D)                         \[72{{s}^{2}}\]

    Correct Answer: C

    Solution :

    \[\underset{\begin{smallmatrix}  \text{s mole litr}{{\text{e}}^{-1}} \\  \text{(soluble)} \end{smallmatrix}}{\mathop{{{a}_{3}}{{(P{{O}_{4}})}_{2}}}}\,\xrightarrow{{}}\underset{\begin{smallmatrix}  \text{3s mole} \\  \text{litr}{{\text{e}}^{-1}} \end{smallmatrix}}{\mathop{3C{{a}^{2+}}}}\,+\underset{\begin{smallmatrix}  \text{2s mole} \\  \text{litr}{{\text{e}}^{-1}} \end{smallmatrix}}{\mathop{2P{{O}_{4}}^{3-}}}\,\] \[{{K}_{sp}}\] of \[C{{a}_{3}}{{(P{{O}_{4}})}_{2}}=3{{[C{{a}^{+\,+}}]}^{3}}+{{[P{{O}_{4}}^{3-}]}^{2}}\]                 \[={{(3s)}^{3}}\times {{(2s)}^{2}}\]                 \[=27{{s}^{3}}\times 4{{s}^{2}}=108{{s}^{5}}\]


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