RAJASTHAN PMT Rajasthan - PMT Solved Paper-1996

  • question_answer
    The electronic configuration of \[Na\] is\[2,8,1\]. How many proton and electron of it?

    A)  \[11,11\]                            

    B)                         \[2,3\]                 

    C)                         \[5,2\]                                 

    D)                         \[3,5\]

    Correct Answer: A

    Solution :

    \[_{11}Na=2,8,1\] Electron = proton = atomic number


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