2. Solved Papers
  3. RAJASTHAN PMT

RAJASTHAN PMT Rajasthan - PMT Solved Paper-1996

  • question_answer
    Two sirens 1 km apart are producing sound by \[330\,Hz\]an observer is coming towards a siren from another siren, then apparent frequency will be:

    A)  \[8\,Hz\]                                            

    B)         \[4\,Hz\]                            

    C)         \[6\,Hz\]                                            

    D)         \[1\,Hz\]

    Correct Answer: B

    Solution :

    Apparent frequency \[\Delta n=\frac{2{{\upsilon }_{0}}}{\upsilon }\times n\] Where \[{{\upsilon }_{0}}\] = speed of observer \[\upsilon \] = speed of sound. \[\Delta n=\frac{2\times 2}{330}\times 330\] n = frequency \[=4Hz\]


You need to login to perform this action.
You will be redirected in 3 sec spinner