2. Solved Papers
  3. RAJASTHAN PMT

RAJASTHAN PMT Rajasthan - PMT Solved Paper-1996

  • question_answer
    The moment of inertia of a thin rod of mass M and length L about an axis through one of its ends and perpendiculars length is:

    A) \[\frac{M{{L}^{2}}}{3}\]                                

    B)        \[\frac{M{{L}^{2}}}{12}\]                             

    C)        \[\frac{M{{L}^{2}}}{2}\]                                

    D)        \[\frac{M{{L}^{2}}}{13}\]

    Correct Answer: B

    Solution :

    Moment of inertia of thin rod, with respect to its centre \[I=\frac{M{{L}^{2}}}{12}\]


You need to login to perform this action.
You will be redirected in 3 sec spinner