RAJASTHAN PMT Rajasthan - PMT Solved Paper-1996

  • question_answer
    If resonance frequency is f and then the capacity is increased 4 times, then new resonance frequency will be:

    A)  \[f\text{/2}\]                                                   

    B)         \[2f\]                                   

    C)         \[f\]                                                     

    D)         \[f\text{/4}\]

    Correct Answer: A

    Solution :

    \[f\propto \frac{1}{\sqrt{C}}\] if frequency is made 4 times then frequency becomes half.


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