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RAJASTHAN PMT Rajasthan - PMT Solved Paper-1996

  • question_answer
    The velocity of sound in air is \[333\text{ }m/s,\] if the fundamental frequency of an open pipe is 333 Hz Then length of the pipe required to produce second over tone is:

    A)  \[0.5m\]                                             

    B)         \[1.0m\]                             

    C)         \[1.5m\]                                             

    D)         \[2m\]

    Correct Answer: A

    Solution :

    \[{{n}_{3}}=\frac{3\upsilon }{2L},\,\upsilon =333m/s\] On solving \[L=0.5m,\,\,{{n}_{3}}=333m/s\]


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