A) methane
B) propene
C) ethane
D) none of these
Correct Answer: A
Solution :
\[\underset{Ethene}{\mathop{C{{H}_{2}}}}\,=C{{H}_{2}}+\underset{Methane}{\mathop{C{{H}_{4}}}}\,\xrightarrow{{}}\underset{\text{Propane}}{\mathop{C{{H}_{3}}C{{H}_{2}}C{{H}_{3}}}}\,\]
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