A) \[\text{ }\!\![\!\!\text{ }{{\text{M}}^{\text{0}}}{{\text{L}}^{\text{-1}}}{{\text{T}}^{\text{0}}}{{\text{A}}^{\text{1}}}\text{ }\!\!]\!\!\text{ }\]
B) \[\text{ }\!\![\!\!\text{ }{{\text{M}}^{1}}{{\text{L}}^{\text{1}}}{{\text{T}}^{\text{-2}}}{{\text{A}}^{\text{-1}}}\text{ }\!\!]\!\!\text{ }\]
C) \[\text{ }\!\![\!\!\text{ }{{\text{M}}^{1}}{{\text{L}}^{0}}{{\text{T}}^{\text{-2}}}{{\text{A}}^{\text{-1}}}\text{ }\!\!]\!\!\text{ }\]
D) \[\text{ }\!\![\!\!\text{ }{{\text{M}}^{1}}{{\text{L}}^{1}}{{\text{T}}^{\text{-2}}}{{\text{A}}^{\text{1}}}\text{ }\!\!]\!\!\text{ }\]
Correct Answer: C
Solution :
From the formula \[F=q\upsilon B\] \[B=\frac{F}{q\upsilon }=\frac{ma}{it\upsilon }\] \[=\frac{[ML{{T}^{-2}}]}{[AT]\,[L{{T}^{-1}}]}=[{{M}^{1}}{{L}^{0}}{{T}^{-2}}{{A}^{-1}}]\]
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