RAJASTHAN PMT Rajasthan - PMT Solved Paper-1997

  • question_answer
    If mass and radius of a hollow sphere are M and R respectively, then its moment of inertia, w.r.t. its diameter is :

    A)  \[\frac{2}{5}M{{R}^{2}}\]

    B)                                        \[\frac{2}{3}M{{R}^{2}}\]

    C)  \[\frac{1}{2}M{{R}^{2}}\]            

    D)                        \[M{{R}^{2}}\]

    Correct Answer: B

    Solution :

    Moment of inertia of spherical shell \[=\frac{2}{3}M{{R}^{2}}\]


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