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RAJASTHAN PMT Rajasthan - PMT Solved Paper-1997

  • question_answer
    The time of flight and range of a projectile are 10 second and 500 m respectively. The maximum height obtained by it will be:

    A)  125 m                  

    B)         50 m                    

    C)  100 m                  

    D)         150 m

    Correct Answer: A

    Solution :

    Using the equations of projectile flight time \[T=\frac{2u\,\sin \theta }{g}\] \[10=\frac{2u\,\,\sin \theta }{g}\]                 \[\Rightarrow \]               \[u\,\sin \theta =5g\]                 Height   \[h=\frac{{{u}^{2}}\,{{\sin }^{2}}\theta }{2g}=\frac{25{{g}^{2}}}{2g}=125m\]


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