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RAJASTHAN PMT Rajasthan - PMT Solved Paper-1997

  • question_answer
    lionization energy of hydrogen atom is 13.6 \[\text{eV}\text{.}\,\text{If}\,\text{h=6}\text{.6 }\!\!\times\!\!\text{ 1}{{\text{0}}^{\text{-34}\,}}\text{Joule-sec,}\]then value of R (Rydberg constant) will be:

    A)  \[{{10}^{10}}\] per metre  

    B)         \[{{10}^{7}}\] per metre  

    C)                         \[{{10}^{4}}\] per metre   

    D)         \[{{10}^{-7}}\] per metre

    Correct Answer: B

    Solution :

    Rydberg constant \[R=-\frac{E}{ch}\] \[=-\frac{13.6\times 1.6\times {{10}^{-19}}}{3\times {{10}^{8}}\times 6.6\times {{10}^{-34}}}\] \[={{10}^{7}}\]per metre


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