RAJASTHAN PMT Rajasthan - PMT Solved Paper-1998

  • question_answer
    The solubility product of \[BaS{{O}_{4}}\]is \[25\times {{10}^{-12}}\]. What will be the solubility of this:

    A)  \[5\times {{10}^{-6}}mole/litre\]

    B)                         \[25\times {{10}^{-6}}mole/litre\]

    C)                         \[5\times {{10}^{-12}}mole/litre\]

    D)                         \[25\times {{10}^{-12}}mole/litre\]

    Correct Answer: A

    Solution :

    \[BaS{{O}_{4}}B{{a}^{++}}+S{{O}^{-\,\,\,-}}\] \[s=\sqrt{Ksp}\] \[s=\sqrt{25\times {{10}^{-12}}}\] \[s=5\times {{10}^{-6}}mole/litre\]


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