A) \[Fe{{(CN)}_{6}}^{-4}\]
B) \[NaCN\]
C) \[{{C}_{6}}{{H}_{5}}-CN\]
D) \[C{{H}_{3}}CN\]
Correct Answer: B
Solution :
\[A{{g}_{2}}S+2NaCN2gCN+N{{a}_{2}}S\] \[NaCN+AgCN\xrightarrow{{}}Na[Ag{{(CN)}_{2}}]\]
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