RAJASTHAN PMT Rajasthan - PMT Solved Paper-1998

  • question_answer
    What will be the ratio of the radius of second and third orbits of hydrogen?

    A)  \[9:4\]                                 

    B)                         \[2:3\] 

    C)                         \[3:2\]                                 

    D)                         \[4:9\]

    Correct Answer: D

    Solution :

    Radius of orbit \[r=0.529\times \frac{{{n}^{2}}}{2}\overset{\text{o}}{\mathop{\text{A}}}\,\] \[\therefore \]  \[\frac{{{r}_{2}}}{{{r}_{3}}}=\frac{0.529\times \frac{4}{1}}{0.529\times \frac{9}{2}}=\frac{4}{9}=4:9\]


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