A) propanol
B) 2-butanol
C) both (a) and (c)
D) none of these
Correct Answer: B
Solution :
\[C{{H}_{3}}-\underset{O}{\mathop{\underset{||}{\mathop{C}}\,}}\,-H+{{C}_{2}}{{H}_{5}}MgBr\xrightarrow{{}}\] \[C{{H}_{3}}-\underset{{{C}_{2}}{{H}_{5}}}{\mathop{\underset{|}{\mathop{\overset{H}{\mathop{\overset{|}{\mathop{C}}\,}}\,}}\,}}\,-OMgBr\xrightarrow{H.OH}\] \[\underset{2-\text{butanol}}{\mathop{C{{H}_{3}}-\underset{{{C}_{2}}{{H}_{5}}}{\mathop{\underset{|}{\mathop{C}}\,}}\,HOH+Mg(OH)Br}}\,\]
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