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RAJASTHAN PMT Rajasthan - PMT Solved Paper-1998

  • question_answer
    White light is used in Youngs double slits experiment, distance between two slits is \[B(>>b),\]dispersion of interference film is small wavelength of one fringe then calculate wavelength of fringe :

    A) \[\frac{{{b}^{2}}}{B}\]                   

    B)        \[\frac{2{{b}^{2}}}{B}\]

    C) \[\frac{{{b}^{2}}}{B}\frac{{{b}^{2}}}{3B}\]                            

    D)         all of these

    Correct Answer: C

    Solution :

    If the distance between slit and screen B is greater than the separation between slits b i.e.,        \[B>>b\] then at \[\lambda =\frac{{{b}^{2}}}{B}\frac{{{b}^{2}}}{3B}\]we get no fringe.


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