A) \[\frac{1}{2}\frac{1}{2}\]
B) \[-\frac{1}{2}\frac{1}{2}\]
C) \[-\frac{1}{2}\frac{1}{3}\]
D) \[\frac{1}{2}-\frac{1}{2}\]
Correct Answer: D
Solution :
Time period \[T=2\pi \sqrt{\frac{m}{k}}\] \[\therefore \] \[\frac{1}{T}=\frac{1}{2\pi }{{k}^{1/2}}\,{{m}^{-1/2}}\] \[(C{{m}^{x}}{{k}^{y}})=\frac{1}{2\pi }{{k}^{1/2}}{{m}^{-1/2}}\] \[x=\frac{1}{2},y=-\frac{1}{2}\]
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