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RAJASTHAN PMT Rajasthan - PMT Solved Paper-1998

  • question_answer
    The equation of a wave is  \[y={{10}^{-4}}\,\sin \,(60t+2x),\]where\[x\] and\[y\] are in metre,\[t\] in sec, then which statement is true?

    A)  Wavelength is \[\pi \] meter

    B)  Frequency is \[\left( \frac{30}{\pi } \right)\]Hz

    C)  Velocity is 30 m/s

    D)  All of these

    Correct Answer: B

    Solution :

    Equation of wave \[y={{10}^{-4}}\sin (60t+2x)\] Comparing this equation with                 \[y=a\sin (\omega t+kx)\]                 \[\omega =60\]                 \[n=\frac{\omega }{2\pi }=\frac{60}{2\pi }=\frac{30}{\pi }\] \[\therefore \] statement (b) is correct.


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