A) n-hexane
B) 2, 3 dimethyl butane
C) n-hexene
D) \[C{{H}_{3}}-CH=C{{H}_{2}}\]
Correct Answer: B
Solution :
\[CH-\underset{C{{H}_{3}}}{\mathop{\underset{|}{\mathop{C}}\,}}\,H-Cl+2Na+CH-\underset{C{{H}_{3}}}{\mathop{\underset{|}{\mathop{C}}\,}}\,H-Cl\to \] \[\underset{\text{2,3}\,\text{di-methyl}\,\text{butane}}{\mathop{C{{H}_{3}}-\underset{C{{H}_{3}}}{\mathop{\underset{|}{\mathop{C}}\,}}\,H-\underset{C{{H}_{3}}}{\mathop{\underset{|}{\mathop{C}}\,}}\,H-C{{H}_{3}}}}\,\]
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